Find h so that the set S is linearly dependent S 1 2 32 4 1

Find h so that the set S is linearly dependent. S = [|1 2 -3||-2 -4 1||-1 1 h|]

Solution

Find the pivot in the 1st column in the 1st row

Multiply the 1st row by 3

Subtract the 1st row from the 2nd

Multiply the 1st row by -1

Subtract the 1st row from the 3rd row and restore it

2(h-3)+20=0

2h-6+20=0

2h+14=0

2h=-14

h=-7 answer

Find the pivot in the 1st column in the 1st row X1 X2 b 1 1 -2 -1 2 3 -4 1 3 -3 1 h Multiply the 1st row by 3 X1 X2 b 1 3 -6 -3 2 3 -4 1 3 -3 1 h Subtract the 1st row from the 2nd X1 X2 b 1 3 -6 -3 2 0 2 4 3 -3 1 h Multiply the 1st row by -1 X1 X2 b 1 -3 6 3 2 0 2 4 3 -3 1 h Subtract the 1st row from the 3rd row and restore it X1 X2 b 1 1 -2 -1 2 0 2 4 3 0 -5 h-3
2(h-3)+20=0 2h-6+20=0 2h+14=0 2h=-14 h=-7 answer