Discuss the uniform convergence of the sequence of functions
Discuss the uniform convergence of the sequence of functions f_n(x) = nxe^-nx^2 on the interval (i) [0, 1] and (ii) on the interval [1, infinity).
Solution
First of all, observe that fn(0) = 0 for every n in N. So the sequence {fn(0)} is constant and converges to zero.
(i) Now suppose 0 < x < 1
fn(0) = nxe-nx2
But -x2< 0 when 0 < x < 1, it follows that
lim fn(x) = 0 for 0 < x < 1
n
Finally, fn(1) = ne-n for all n.
So,lim fn(x) =
n
Therefore, {fn} is not pointwise convergent on [0, 1].
(ii) for [1, )
For every real number x, we have:
lim fn(x) = lim nxe-nx2 = 0
n n
Thus, {fn} converges pointwise in interval [1,)
![Discuss the uniform convergence of the sequence of functions f_n(x) = nxe^-nx^2 on the interval (i) [0, 1] and (ii) on the interval [1, infinity). SolutionFirs Discuss the uniform convergence of the sequence of functions f_n(x) = nxe^-nx^2 on the interval (i) [0, 1] and (ii) on the interval [1, infinity). SolutionFirs](/WebImages/27/discuss-the-uniform-convergence-of-the-sequence-of-functions-1071718-1761561472-0.webp)