C https EN EN by Apps BN AC ciroultry Problem 3520 Problem 3

++C https:/ EN EN by Apps BN AC ciroultry Problem 35.20 Problem 35.20 Part A An inductor is connected to a 20 kHz oscillator. The peak current is 67 mA when the ms voltage is 6.8 V What is the value of the inductance L Express your answer to two significant figures and include the appropriate units 1 Value Units Submit My Answers Give Up

Solution

Rms current

I_rms=I_peak/sqrt[2] =67/sqrt[2] =47.38 mA

Inductive rectance

X_L=V_rms/I_rms=6.8/(47.38*10^-3) =143.53 ohms

since X_L=2pifL

SO Inductance

L=X_L/2pif =143.53/(20*10³)

L=7.18*10^-3 H or 7.18 mH