The reaction CHCl2g Cl2g rightarrow CCl2g HClg ahs the fol

The reaction CHCl_2(g) + Cl_2(g) rightarrow CCl_2(g) + HCl(g) ahs the following rate law: Rate = k[CHCl_3][Cl_2]. If the concentration of CHCl_3 is decreased by a factor of five while the concentration of Cl_2 is kept the same, the rate will _____ double. decrease by a factor of one-fifth. stay the same. triple. increase by a factor of five

Solution

ans: b) decrease by a factor of one-fifth.

bacause we know E = E`+ln(reactants/products)

E=E`+ln([CHCL2][CL2]/([CCL2][HCL])

from this we can say that [CHCL2][CL2] should be 1.so, the concentration of CHCL2 is 5times then the cocentration of CL2 will be one-fifth of it.