1 a 12 l of 03 mgml galactosidase is added to 3 ml of assay

1.

a)

12 l of 0.3 mg/ml -galactosidase is added to 3 ml of assay buffer. How many g of -galactosidase are in the assay tube?

a) 0.004 g

b) 40 g

c) 3.6 g

d) 3,600 g

b)

You use 0.5 mg/ml -galactosidase to create 3 ml of assay buffer containing 3 g of -galactosidase. By what dilution factor has the -galactosidase in the assay tube been diluted?

a) 6,000
b) I don\'t have enough information to answer this question.

c) 18

d) 500

Solution

1a. C1 x V1 = C2 x V2

C1 = 0.3 mg/ml, V1=  12 l. C2 =?, V2= 3012 l.

Substituting values in equation, C2 can be determined.

C2 = (C1.V1)/V2 = (0.3x12)/3012 = 0.0012mg/ml = 1.2 g/ml

So in 3 ml solution, amount of -galactosidase = 3x 1.2 g= 3.6g.

Hence, the correct answer is option c.

1b) C1 x V1 = C2 x V2;

3 ml of assay buffer containing 3 g of -galactosidase means 1g/ml.

C1 = 0.5 mg/ml= 500g/ml, V1 =?, C2 =1g/ml, V2(Final volume) = 3ml = 3000l

V1 = 3000/500= 6l

Dilution factor = V final/ V initial = 3000/6 = 500.

Hence the correct answer is option d.