2xx 3 6x 3 28x2 9Solution2xx3 6x3 28x29 2xx3 6x3x3x3 28

Solution

[2x/(x-3)] +[6/(x+3)] =28/(x²-9)

[(2x(x+3)) +(6(x-3))]/[(x-3)(x+3)] =28/(x²-9)

(a+b)*(a-b)=a²-b²

[(2x²+6x) +(6x -18)]/(x²-3²) =28/(x²-9)

(2x²+12x -18)/(x²-9) =28/(x²-9)

(2x²+12x -18)  =28

2x²+12x -46=0

x²+6x -23=0

ax^2 +bx +c =0 ==>x=[-b+(b²-4ac)]/(2a),x=[-b-(b²-4ac)]/(2a) , here a=1,b=6 , c=-23

x=[-6+(6²-4*1*(-23))]/(2*1),x=[-6-(6²-4*1*(-23))]/(2*1)

x=[-6+(6²-4*1*(-23))]/(2*1),x=[-6-(6²-4*1*(-23))]/(2*1)

x=-3+42, x=-3 +42