Please show your work stepbystep Work on problem number 15 a
Please show your work step-by-step.
Work on problem number 15 (a-c) on page 7-70
Solution
We first get the z score for the critical value. As z = (x - u) sqrt(n) / s, then as          
           
 x = critical value =    55      
 u = mean =    52      
 n = sample size =    10      
 s = standard deviation =    4.74341649      
           
 Thus,          
           
 z =    2      
           
 Thus, using a table/technology, the right tailed area of this is          
           
 P(z >   2   ) =    0.022750132 [ANSWER, PART A]
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We first get the z score for the two values. As z = (x - u) sqrt(n) / s, then as          
 x1 = lower bound =    50      
 x2 = upper bound =    60      
 u = mean =    52      
 n = sample size =    10      
 s = standard deviation =    4.74341649      
           
 Thus, the two z scores are          
           
 z1 = lower z score =    -1.333333333      
 z2 = upper z score =    5.333333333      
           
 Using table/technology, the left tailed areas between these z scores is          
           
 P(z < z1) =    0.09121122      
 P(z < z2) =    0.999999952      
           
 Thus, the area between them, by subtracting these areas, is          
           
 P(z1 < z < z2) =    0.908788732   [ANSWER, PART B]  
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We first get the z score for the critical value. As z = (x - u) sqrt(n) / s, then as          
           
 x = critical value =    55      
 u = mean =    52      
 n = sample size =    10      
 s = standard deviation =    4.74341649      
           
 Thus,          
           
 z =    2      
           
 Thus, using a table/technology, the left tailed area of this is          
           
 P(z >   2   ) =    0.977249868 [ANSWER, PART C]
           
   


