1 A 10 mol sample of helium gas has a temprature of 27 celsi

1) A 1.0 mol sample of helium gas has a temprature of 27 celsius. What is the total kinetic energy of all the gas atoms in the sample? How fast would a 65-kg person have to run to have the same kinetic energy??

2) What is the dew point if the humudity is 75% on a day when the temprature is 25 celsius??

Solution

1.

Kinetic energy

KE =(3/2)nRT =(3/2)*1*8.31*(273.2+27)

KE=3742 J or 3.742 KJ

For a 65 Kg person to have same Kinetic energy ,his speed should be

KE =(1/2)mV²=3742

(1/2)*65*V²=3742

V=10.73 m/s

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2.

Dew point temperature is given by

T_d=T-(100-RH)/5 =25-(100-75)/5

T_d=20^oC