A 80Hz unipolar square wave has a duty cycle of D 02 and ha
A 80-Hz unipolar square wave has a duty cycle of D = 0.2 and has an amplitude of 5 V. What is the ratio of the ON time to to the OFF tune?
Solution
duty cycle=Ton/(Ton+Toff)=0.2
frequency f=80 hertz
T=1/f=1/80=0.0125
Ton/0.0125=0.2
Ton=0.2*0.0125=2.5*10^-3
T=Ton+Toff
Toff=T-Ton=0.0125-2.5*10^-3=0.01
Ton/Toff=(2.5*10^-3)/(0.01)=0.25
