a You have a box that measures 2 meters x 2 meters x 10 mete

Solution

The diagonal would have to be LONGER than 10 meters. So yes, use the pythagorean theorem twice.

1st time: 10^2 + 2^2 = c^2
c = 10.198 This is the length of the diagonal of the triangle ALONG THE FLOOR of the box.

Now find the diagonal from the bottom right corner to the top left corner of the box.

c^2 = 10.198^2 + 2^2
c^2 = 108

c = 10.39 m = the longest piece of rebar that could fit in this box.

You can not write multi questions in a single question , you should write all question seperately.

Any how I am giving you the hint to solve this question, please go through it. If you have still doubt and want a solution please ask this question seperately. Thanks.

The equation of the line passing through (x1,y1) and (x2, y2) is ---
                           ( y2 - y1 )
=> ( y - y1 ) = ---------------------- multiplied by ( x - x1 ) .................. (1)
( x2 - x1 )

algebraically,

an x-intercept is a point on the graph where y is zero, and

a y-intercept is a point on the graph where x is zero.

More specifically,

an x-intercept is a point in the equation where the y-value is zero, and

a y-intercept is a point in the equation where the x-value is zero.

For finding the angle

Rearrange the equation with y on one side and x on the other.

Find the x and y intercept. You\'ll then get to form a right angle triangle with the lengths.

Find the angle. Hint use cosine rule.