A service station has 39 octane and 78 octane gasoline How m

A service station has 39 octane and 78 octane gasoline. How many liters of each gasoline should be mixed to provide 13 liters of 72 octane gasoline for a chemistry experiment?

Solution

Given there is a service station with 39 octane and 78 octane gasoline.
Some quantity of these two is mixed to provide 13 liters of 72 octane gasoline.
Let A liters is takan from 39 octane gasoline and B liters is taken from 78 octane gasoline.
which provides a total of 13 litres of 72 octane gasoline.

It can be tken in equation form as 39A+78B=13*72

39A+78B=936

Total liters of A and B is 13

A+B=13

A=13-B

Substitute \'A\' in 39A+78B=936

39(13-B)+78B=936

507-39B+78B=936

-39B+78B=936-507

39B=429

B=429/39

B=11

To find A:A=13-B

A=13-11

A=2

Therefore, 2 liters of  39 octane gasoline and 11 liters of 78 octane gasoline are mixed  to provide 13 liters of 72 octane gasoline for a chemistry experiment.