Solve the right triangle ABC with C 90Degree B 630Degree b

Solve the right triangle ABC, with C = 90Degree. B = 63.0Degree, b = 121 in In the right triangle ABC, with C = 90Degree, A = Degree. (Simplify your answer. Type an integer or a decimal.) The length of side a is approximately in. (Simplify your answer. Type an integer or a decimal. Round to the nearest tenth as needed.) The length of side c is approximately in. (Simplify your answer. Type an integer or a decimal. Round to the nearest tenth as needed.)

Solution

B=63^o, C=90^o ,b =121 in

A+B+C =180⁰

A=180⁰-B-C

A=180-90-63

A=27⁰

by law of sines a/sinA =b/sinB =c/sinC

a/sinA =b/sinB

a/sin27⁰ =121/sin63⁰

a=121sin27⁰/sin63⁰

a=61.7 in

c/sinC =b/sinB

c/sin90⁰ =121/sin63⁰

c =121/sin63⁰

c=135.8in