A 08 m length of wire is formed into a single turn square lo

A 0.8 m length of wire is formed into a single turn, square loop in which there is a current of 12 A. The loop is placed in magnetic field of 0.12 T, which is perpendicular to a normal to the loop plane. What is the maximum torque that the loop can experience?

Solution

wire is turned into square loop

so 4L = 0.8 m

L = 0.2 m

area A = L^2 = 0.2^2

maximum torque = NIAB

      = 1 x 12 x 0.2^2 x 0.12

= 0.0576 N m