A transducer that can be modeled as an opencircuit voltage o

A transducer that can be modeled as an open-circuit voltage of 0.8V in series with a source resistance (Thevenin equivalent resistance) of 1.5M Ohm is to be connected to an amplifier with a 2k Ohm input resistance. Thus, the input of the amplifier is the \"load\" of the transducer. Calculate the load voltage (across the 2k Ohm input resistance of the amplifier) if the connection is done a. directly or a. through an ideal unity-gain voltage follower.

Solution

Ans)

Load Voltage when load is directly connected is

VL=0.8*2k/(1.5M+2k) Voltage division rule

VL=0.8*2k/1.502M=0.001065 V=1.065 mV

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Load Voltage when load is connected through ideal unity gain voltage follower

Input Impedance of ideal unity gain voltage follower=infinity

VL=0.8*infinity/(1.5M+infinity) Voltage division rule

basically this acts as open circuit so current will be zero ,so no voltage drop in the series resistance

hence VL=0.8 V