o TMobile 416 PM edugenwileypluscom C University Physics Uni
     o T-Mobile 4:16 PM edugen.wileyplus.com C University Physics (University Physics Open Assignment Chapter 31, Problem 065 An ac generator provides emf to a resist v load r. remote factory over twease n ine. At the factory a step-down transformer reduces the voltage from its (rms) transmission value Ve to a much lower value that is safe convenient for use in the factory The transmission linn ressate sos atable, the power of the generator is 256 kW Ir V83 kV what are (a) the voltage decrease Valong the transmission line and (b) the rate Pa at which energy is dissipated in the line as themal energy? 8.8 ky, what are (cavand (d) Pg, If V.. 1.1 kv, what are (e) avand (f)  
  
  Solution
a)
Rms current in the cable
Irms=P/Vt =(256*103)/(83*103) =3.08 A
The Rms Voltage drop
Vrms=IrmsR=3.08*(2*0.63)=3.886 Volts
b)
The Rate of energy Dissipation is
Pd=Irms2R=3.082*(2*0.63)=11.99 W
Pd=12 W (approx)
c)
Irms=256*103/(8.8*103) =29.1 A
Vrms=29.1*(2*0.63) =36.65 Volts
d)
Pd=28.42*(2*0.63)=1066.3 W
e)
Irms=256*103/(1.1*103) =232.72 A
Vrms=232.72*(2*0.63) =293.24 Volts
f)
Pd=232.722*(2*0.63)=68244.1 W

