Given a triangle with a 11 gamma 35 degree and beta 16 de

Given a triangle with a = 11, gamma = 35 degree, and beta = 16 degree, what is the length of c? Round the answer to two decimals places. c = 5.29 c = 8.12 c = 22.89 c = 31.01 Given a triangle with a = 9, b = 11, alpha = 31 degree, what is (are) the possible length(s) of c? c = 16.42 or 2.44 c = 14.21 c = 16.42 or 3.41 c=6.61 Given a triangle with b = 6, c = 7, and alpha = 146 degree, what is the length of a? Round the answer to two decimal places. a = 10.95 a = 12.44 a = 3.92 a = 4.65 Find the area of a triangle with sides 4 m, 5 m, and 7 m. Round to the nearest hundredth. 9.80 m^2 16.00 m^2 10 00 m^2 3.46 m^2 Find the area of the triangle with alpha = 83degree, b = 9 feet, and c = 6 feet 27.00 ft^2 329 ft^2 0 26.80 ft^2 53.60 ft^2 Because of prevailing winds, a tree grew so that it was leaning 8 degree from the vertical. At a point 45 meters from the tree, the angle of elevation to the top of the tree is 30 degree (see figure). Find the height a of the tree. 28.55 m 30.55 m 27.55 m 26.55 m 29.55 m

Solution

32)let a= 9 and b=11 be the two sides of the rigt angled triangle then the hypotenuse c=

sqrt(a²⁺b²)=sqrt(121+81)= 14.21

therefore,the option B) is the right answer.

34) let side AB= 5m ,let side AC=4m and let side BC = 7m

Therefore area of the triangle ABC= 0.5*base *height

=0.5 * AB * AC =0.5 *5*4= 10m²