A proton is moving due north is a magnetic field directed do

A proton is moving due north is a magnetic field directed downward at a 90 degree angle to the horizontal. The direction of the magnetic force is up down east west south north An ac generator with peak voltage 100 volts is placed across a 10-ohms resistor. What is the average power dissipated? 100 W 150 W 500 W 1000 W 2000W A 3.5 H inductor in series with a 2-kohms resistor is connected to a 60-Hz source. Calculate the impedance the circuit. 1500 ohms 1800 ohms 2100 ohms 2400 ohms 8600 ohms  find the resonant frequency for a series RLC circuit where R = 10 ohms, C = 5 ohms, and L = 2 mH. 998 Hz 1592 Hz C. 2.45 kHz 11.3 kHz 2.53 kHz In an AC circuit the voltage across the inductor Leads current by 45 degrees Lags current by 45 degrees Leads voltage across the capacitor by 180 degrees Leads voltage across the capacitor by 90 degrees In an AC circuit the capacitive reactance is equal to the inductive reactance. In this case the phase angle is 180 degree 0 degree minim 90 degree 90 degree minim 45 degree

Solution

5.
for proton, q = +ve

v = +j

B = - k

Fb = q ( v X B )

    = + (j x (-k)) = - i

direction of force is toward west.

6. P = Vrms^2 / R

and Vrms = Vpeak / sqrt(2)

P = Vpeak^2 / 2R = 100^2 / (2 x 10) = 500 W

7. Reactance of inductor = 2 pi f L

XL = 2 x pi x 60 x 3.5 = 1319.5 ohm

R = 2000 ohm

impedance = sqrt(R^2 + XL^2) = 2396 ohm

Ans(d)

8. resonannt frequency, f0 = 1 / 2pi sqrt(LC) =1 / 2pisqrt(5 x 10^-6 x 2 x 10^-3)

f0 = 1 / (2 x pi x 10^-4)   =1591.5 Hz

Ans(b)

9. (d)

10. 0 deg Ans(b)