A coil with 231 turns has a magnetic flux of 62 7 nTn2 throu

A coil with 231 turns has a magnetic flux of 62. 7 nT-n^2 through each turn when the current is 2. 47 mA. (a) What is the inductance of the coil? What are the (b) inductance and (c) flux through each turn when the current is increased to 6. 11 mA? (d) What is the maximum emf e across the coil when the current through it is given by i = (4. 29 mA)cos(omegat), where omega = 168 rad/s?

Solution

Inductance = flux linkages / current = 231 * 62.7 * 10^-9 / 2.47 * 10^-3

= 0.00586 H

---------------------------------------------------

Flux = inductance * current/turns = 0.00586 * 6.11 * 10^-3 / 231

= 1.55 * 10^-7 T

----------------------------------------------------

e =L di / dt = L d (i cos w t)/dt = L i w sin wt

maximum emf = L i w = 0.00586 * 4.29 * 10^-3 * 168

= 0.00422 volts