RedGreen colorblindness is a Xlinked recessive disorder Hunt
Solution
We first need to know what susan\'s genotypes are:
since her father had huntington\'s and color blindess and mother did not have any, the crosses would be :
and
this explains that susan is a carrier for color blindness XCXc and could be a carrier for huntington\'s as well
chances of susan being a carrier for huntington\'s is 50% or 1/2
since her husband does not have an family history of both the diseases, we will assume he is not a carrier for both, since we have to find out the chances of them having a girl child with normal vision and having huntington\'s , we would assume susan is a carrier. the crosses would be as follows:
and
chances of having a girl are 1/2 chances of girl having normal vision are 1/2 and chances of having huntington\'s is 1/2 as well . here we can also take into account the chances of Susan having huntington\'s is 1/2 as well
therefore, it would be - 1/2 x 1/2 x 1/2 x 1/2 = 1/16
| Hh | Hh |
| hh | hh |
