find the margin of error for the given values of c s and n c

find the margin of error for the given values of c, s, and n

c=0.90

s=2.9

n=36

E=???

Solution

margin of error is:

E = z * s / ?n

For a 90% confidence interval, use z = 1.645.

Substituting the value for z, s, and n gives:

E = (1.645)(2.9) / ?36

E = 0.7950833
=0.7951 (rounded to four decimal places)