e6b9 Im having trouble defining if they are in series E6B9 I
e6b.9 I\'m having trouble defining if they are in series
Solution
Answer:
(a)
Bulbs A and B are not in series, the equivalent resistance of bullbs B and C will be in series with resistance of A
In seies the current remains the same, let I be the current flowing through bulb A now this current divides in B and C
this implies that current would not be same in B as in A, So both A nad B are not in series.
(b)
Req of B and C = (12 x 12)/ 24 = 6 ohm
Now this is in series with A
R total = 6 + 12 = 18 ohm
