Find theta a and c Solutionsum of angles in a triangle 1800

Find theta, a, and c.

sum of angles in a triangle =180⁰

+90⁰+47⁰ =180⁰

=43⁰

by law of sines

a/sin43^o =6/sin47^o =c/sin90^o

a/sin43^o =6/sin47^o

a=6sin43^o /sin47^o

a=5.595

c/sin90^o=6/sin47^o

c=6sin90^o/sin47^o

c=8.204

Find theta, a, and c. Solutionsum of angles in a triangle =1800 +900+470 =1800 =430 by law of sines a/sin43o =6/sin47o =c/sin90o a/sin43o =6/sin47o a=6sin43o /

Tutor

Dr Jack

Tutor: Dr Jack

Most rated tutor on our site