In the probability statement PF75 Solution14 As df1 7 df2
Solution
14.
As df1 = 7, df2 = 5, and the left tailed area of Q is 0.05, then by table/technology,
Q = 0.252 [ANSWER, D]
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15.
Formulating the null and alternatuve hypotheses,          
           
 Ho:   p   =   0.85
 Ha:   p   =/=   0.85
 As we see, the hypothesized po =   0.85      
 Getting the point estimate of p, p^,          
           
 p^ = x / n =    0.666666667      
           
 Getting the standard error of p^, sp,          
           
 sp = sqrt[po (1 - po)/n] =    0.053229065      
           
 Getting the z statistic,          
           
 z = (p^ - po)/sp =    -3.38      
           
 As this is a    2   tailed test, then, getting the p value,  
           
 p =    0.00057      
 significance level =    0.05      
As P < 0.05, REJECT THE NULL HYPOTHESIS.
Hence,
OPTION D: -3.38, YES [ANSWER, D]
![In the probability statement, P(F_7,5 Solution14. As df1 = 7, df2 = 5, and the left tailed area of Q is 0.05, then by table/technology, Q = 0.252 [ANSWER, D] *  In the probability statement, P(F_7,5 Solution14. As df1 = 7, df2 = 5, and the left tailed area of Q is 0.05, then by table/technology, Q = 0.252 [ANSWER, D] *](/WebImages/27/in-the-probability-statement-pf75-solution14-as-df1-7-df2-1073115-1761562429-0.webp)
