In the probability statement PF75 Solution14 As df1 7 df2
Solution
14.
As df1 = 7, df2 = 5, and the left tailed area of Q is 0.05, then by table/technology,
Q = 0.252 [ANSWER, D]
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15.
Formulating the null and alternatuve hypotheses,
Ho: p = 0.85
Ha: p =/= 0.85
As we see, the hypothesized po = 0.85
Getting the point estimate of p, p^,
p^ = x / n = 0.666666667
Getting the standard error of p^, sp,
sp = sqrt[po (1 - po)/n] = 0.053229065
Getting the z statistic,
z = (p^ - po)/sp = -3.38
As this is a 2 tailed test, then, getting the p value,
p = 0.00057
significance level = 0.05
As P < 0.05, REJECT THE NULL HYPOTHESIS.
Hence,
OPTION D: -3.38, YES [ANSWER, D]
![In the probability statement, P(F_7,5 Solution14. As df1 = 7, df2 = 5, and the left tailed area of Q is 0.05, then by table/technology, Q = 0.252 [ANSWER, D] * In the probability statement, P(F_7,5 Solution14. As df1 = 7, df2 = 5, and the left tailed area of Q is 0.05, then by table/technology, Q = 0.252 [ANSWER, D] *](/WebImages/27/in-the-probability-statement-pf75-solution14-as-df1-7-df2-1073115-1761562429-0.webp)