Assume that a dihybrid F2 ratio resulting from epistasis was
Assume that a dihybrid F2 ratio, resulting from epistasis, was 9:6:1. If a double heterozygote was crossed with the fully recessive type, what phenotypic ratio is expected among the offspring?
a. 1:1 b. 9:7 c. 1:2:1 d. 2:1 e. 3:1
Solution
Answer: c. 1:2:1
Duplicate genes with cumulative effect (9:6:1):
Certain phenotypic traits depend on the dominant alleles of two gene loci. When two tdominant is present it will show its phenotype. The ratio will be 9: 6: 1.
It means that during dihybrid cross, either of dominant genes or both dominant genes give similar phenotype.
A_bb or aaB_ all these genotypes give the same phenotype. So the Dihybrid cross ratio will be changed from 9:3:3:1 to 9:6:1.
If a double heterozygote was crossed with the fully recessive type,
AaBb x aabb----------Parents
ab
AB
AaBb
Ab
Aabb
aB
aaBb
ab
aabb
1:2:1
| ab | |
| AB | AaBb |
| Ab | Aabb |
| aB | aaBb |
| ab | aabb |
