Suppose a DT periodic signal xn with period N 4 has nonzero
Suppose a DT periodic signal x[n] (with period N = 4) has nonzero Fourier series coefficients a_1 = 5, a_0 = 2, and a_1 = -5. What is the Fourier series coefficient b_-1 for x[n-3] based on the DT Fourier series properties Table 3.2 in the textbook? Selected Answer: 5e^-j3pi/2 Answers: 5e^-j3pi/2 -5e^-j3pi/2 5e^j3pi/2 -5e^j3pi/2
Solution
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![Suppose a DT periodic signal x[n] (with period N = 4) has nonzero Fourier series coefficients a_1 = 5, a_0 = 2, and a_1 = -5. What is the Fourier series coeffi Suppose a DT periodic signal x[n] (with period N = 4) has nonzero Fourier series coefficients a_1 = 5, a_0 = 2, and a_1 = -5. What is the Fourier series coeffi](/WebImages/27/suppose-a-dt-periodic-signal-xn-with-period-n-4-has-nonzero-1073281-1761562546-0.webp)