what is the critical angle for the internal reflection to oc
what is the critical angle for the internal reflection to occur for a material with an index of refraction of 1.526 surrounded by air with n=1
what is the critical angle for the internal reflection to occur for a material with an index of refraction of 1.526 surrounded by air with n=1
what is the critical angle for the internal reflection to occur for a material with an index of refraction of 1.526 surrounded by air with n=1
Solution
n1 sin thetac = n2 sin 90
sin thetac = n2 / n1 = 1 / 1.526
thetac = 40.92 deg
