0021 mol of gas undergoes the process shown in the figure Fi

0.021 mol of gas undergoes the process shown in the figure (Figure 1). What is the final temperature in degree C? Express your answer using two significant figures. What is the final volume V_2 ? Express your answer with the appropriate units.

Solution

We have

PV=nRT

T=P₁V₁/nR

Here Temperture is constant as the process is isothermal.

T =(3*100*10^(-6) )/(0.021)*(8.314*10^-5))

=171.8 K

Again

T=P₂V₂/nR

V₂=nRT/P₂

   _=((0.021)(8.314*10^-5)(171.8 K))/1

=299.9 cm^3

= 300 cm^3(approximately)