Discrete math question Use mathematical induction to prove t
Discrete math question. Use mathematical induction to prove the above.
Summation j = 1 n j 2^j = (n - 1)2^n + 1 + 2Solution
Let us prove for n=1
put n=1
LHS, 1.2=2
RHS = (1-1)22+2 = 2
LHS=RHS
Hence P(n) is true.
Let us assume that P(k) is true.
P(k): (k-1)2k+2+2
Now we have to prove that P(k+1) is true
P(k+1): (k-1+1)2k+1+2+2
(k-1)2k+1+2+2+2k+1+2
2((k-1)2k+2+2k+2)+2
hence it is proved for P(k+1) also.

