The length of a rectangle is 5 times the width If the perime

The length of a rectangle is 5 times the width. If the perimeter is to be at least 48 meters, what are the possible values for the width? [Hint: If the perimeter is at least 48 meters, then it is greater than or equal to 48 meters.] (Let x be the width and enter a solved inequality involving x.)

Solution

Solution:- let the width of the rectangle = x

length = 5x

perimeter = 5x +5x + x +x > = 48

12 x >= 48

x > = 4 m