find the probability P026

find the probability P(0.26<z<1.33) using the standard normal deviation<1.33)>
find the probability P(0.26<z<1.33) using the standard normal deviation<1.33)>
find the probability P(0.26<z<1.33) using the standard normal deviation<1.33)>

Solution

z1 = lower z score =    0.26      
z2 = upper z score =     1.33      
          
Using table/technology, the left tailed areas between these z scores is          
          
P(z < z1) =    0.602568113      
P(z < z2) =    0.908240864      
          
Thus, the area between them, by subtracting these areas, is          
          
P(z1 < z < z2) =    0.305672751   [ANSWER]  

 find the probability P(0.26<z<1.33) using the standard normal deviation<1.33)> find the probability P(0.26<z<1.33) using the standard normal

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