Ax 0 Bx 1 and x 1 Cx can be any real number D1

A.x< 0

B.x< -1 and x > 1

C.x can be any real number

D.-1 <= x < 1

Please explain!

Solution

From taylor series of e^x:

xⁿ/n! = e^x

So for all values of x, the given series is convergent to e^x

Answer C.