solve the integral from 0 to 1 of lnx1x21 I am have extreme

solve the integral from 0 to 1 of (ln(x+1))/(x^2+1). I am have extreme difficulty in solving this. I have tried everything from trig substitutions to creative \"U\" substitutions, none of which have gotten me anywhere. If anyone can figure this one out, it would be GREATLY appreciated. I can easily get the answer using a the Wolfram Alpha calculator, but it can provide no steps on how it got that answer. (the answer is (pi)ln(2)/8))

put x = tan

dx= sec^2 d

so, integral

I = ln(tan+1) *sec^2 d/(tan^2 + 1)

I = ln(tan+1) d from 0 to /4

now apply king that is upper limit + lower limit -x = x

I = integral ln(tan(/4 - )+1)

I = integral ln(2/(1+tan))

I = integral ln(2) - I with the limit = 0 from = /4

2I = /4 ln(2)

I = /8 ln(2)

$solve the integral from 0 to 1 of (ln(x+1))/(x^2+1). I am have extreme difficulty in solving this. I have tried everything from trig substitutions to creative \$

solve the integral from 0 to 1 of lnx1x21 I am have extreme

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