The twostage cascade refrigeration system shown below is use
Solution
Equations :
Power consumption by Compressor for Cycle I = m1 (h7 - h6)
= 416.9(118.97-99.5)
= 8117.04 Btu/hr
= 3.19 hp [ 1 Btu/hr = 0.0000393 hp]
Power consumption by Compressor for Cycle II = m2 (h3 - h2)
= 554.83(61.84 - 53.32)
= 4727.15 Btu/hr
= 1.86 hp
Ratio of mass flow rates = m1/m2
= 416.9/554.83 = 0.7514
In the above equations m1 and m2 are found from following equations :
Given : Lift = 28000 Btu/hr = m2 (h2 - h1) = m2 (53.32 - 2.855)
So, m2 = 554.83 lb/hr
Energy Balance for intermediate heat exchanger (between cycle I and II) :
m1(h6 - h5) = m2(h3-h4)
Or, m1 (99.5 - 21) = 554.83(61.84 - 2.855)
Or, m1 = 416.9 lb/hr
N.B. Here h1 , h2, h3 and h4 are the enthalpy properties for R 503 where data are approximated to close value available in the absence of property table till -180 degF and as well as superheated data.
h5, h6, h7 and h8 are the enthalpy properties for R22 and the data are exact.
