Given this link list opbitrsahopec when you run the program

Given this link list

op->bi->tr->s->a->ho->pec

when you run the program you get the output

s->pec->tr->op->ho->bi->a

Can you comment the code and explain it to me to help me interpret it and understand how that output is produced. The if, else statement in the middle of the body confuses me.

void SLL::MakeIt() {

last->next = first; //What is this line of code doing?

SNode *tmp = first;

int ct = 0;

int s2 = 0;

SNode *tmp2;

while(size > 0) {

if(ct == 2) {

if(s2 == 0) { //how is this if statemnet altering the liked list?

first = tmp->next;

tmp->next = tmp->next->next;

first->next = NULL;

tmp2 = first;

} //if

else { //how is this else statement altering the linked list?

tmp2->next = tmp->next;

tmp->next = tmp->next->next;

tmp2->next->next = NULL;

tmp2 = tmp2->next;

}//else

s2++;

ct = 0;

size--;

}//if

ct++;

tmp = tmp->next;

}//while

last = tmp2;

}

Solution

last->next = first;

first value is asigned to last>next node(added to list )

f(s2 == 0) { //how is this if statemnet altering the liked list?

first = tmp->next;

tmp->next = tmp->next->next;

first->next = NULL;

tmp2 = first;

} //if

meaninf of this check node is first node or not

in case first node then

swap the values form first to next fromat

if any doubts plz forward to me

thank you

the program will check size>0 or not

in case size =0 there is no swap because there is no link or elements

size>0

then check

perticular node is first node or not

its first node then exchange the values and reduce the list size