assessment casa uh eduAssessmentQuizaspx de 43FF14CA53054E4B

assessment casa uh edu/Assessment/Quiz.aspx? de 43FF14CA-5305-4E4B-BFF7-880621 DoB5B7 Question 5 Right triangle ABC is given below. If AB 6, find the area of this triangle. a) 18 V3 9 V3 None of the above.

Solution

AB = 6

area of a triangle is 1/2 * base * height

applying sine rule

sin 60 = perpendicular / hypotenuse

perpendicular = sqrt 3/2 * 6 = 3 sqrt 3

base = sqrt ( 6^2 - 27 ) = 3

therefore, area = 1/2 * 3* 3 sqrt 3 = 9 sqrt 3 / 2 ( ooption d )