Exercise 1323 Algorithmic An experiment has been conducted f

{Exercise 13.23 (Algorithmic)}

An experiment has been conducted for four treatments with eight blocks. Complete the following analysis of variance table (to 2 decimals, if necessary).

Use  = .05 to test for any significant differences.

The p-value is Selectless than .01between .01 and .025between .025 and .05between .05 and .10greater than .10Item 10

What is your conclusion?
SelectConclude not all treatment means are equalDo not reject the assumption that the treatment means are equalItem 11

Source of Variation Sum of Squares Degrees of Freedom Mean Square F
Treatments 1,000
Blocks 300
Error
Total 1,600

Solution

The p-value is 0.01247

The p-value lies between the significance level 0.01 and 0.025.We conclude that the for this significance level we Do not reject the assumption that the treatment means are equalItem 11

Source of Variation Sum of Squares Degrees of Freedom       Mean Square                      F
Treatments 1,000 4-1=3 1000/3=333.33       333.33/42.86=7.77     
Blocks 300 8-1=7 300/7=42.86
Error 300 (4-1)(8-1)=3*7=21 14.28
Total 1,600 32-1=31
{Exercise 13.23 (Algorithmic)} An experiment has been conducted for four treatments with eight blocks. Complete the following analysis of variance table (to 2 d

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