Exercise 1323 Algorithmic An experiment has been conducted f
{Exercise 13.23 (Algorithmic)}
An experiment has been conducted for four treatments with eight blocks. Complete the following analysis of variance table (to 2 decimals, if necessary).
Use = .05 to test for any significant differences.
The p-value is Selectless than .01between .01 and .025between .025 and .05between .05 and .10greater than .10Item 10
What is your conclusion?
SelectConclude not all treatment means are equalDo not reject the assumption that the treatment means are equalItem 11
| Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | F |
| Treatments | 1,000 | |||
| Blocks | 300 | |||
| Error | ||||
| Total | 1,600 |
Solution
The p-value is 0.01247
The p-value lies between the significance level 0.01 and 0.025.We conclude that the for this significance level we Do not reject the assumption that the treatment means are equalItem 11
| Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | F |
| Treatments | 1,000 | 4-1=3 | 1000/3=333.33 | 333.33/42.86=7.77 |
| Blocks | 300 | 8-1=7 | 300/7=42.86 | |
| Error | 300 | (4-1)(8-1)=3*7=21 | 14.28 | |
| Total | 1,600 | 32-1=31 |
