Suppose fxxx1 a f5t b f5t5 c Solve fx7 xSolutionSuppose fxxx

Suppose f(x)=x/x1

(a) f(5/t)=

(b) f(5/t+5)=

(c) Solve f(x)=7 x=

Solution

Suppose f(x)=x/(x1)

(a) f(5/t)=(5/t)/((5/t)1)

f(5/t)=(5/t)/((5t)/t)

f(5/t)=5/(5t)

(b) f(5/(t+5))= (5/(t+5))/((5/(t+5))1)

f(5/(t+5))= (5/(t+5))/((5-t-5)/(t+5))

f(5/(t+5))= -5/t

(c) f(x)=7

x/(x1)=7

x =7x-7

7x-x=7

6x=7

x=7/6