A) The solution inside the cell contains 50% NaCl and ________ water.
B) The beaker contains 25% NaCl and ________ % water.
C) The solution \"inside\" cell #1 is _________ tonic to the solution outside cell #1.
D) The solution \"outside\" cell #1 is ___________ tonic to the solution inside cell #1.
Moss AND TONICITY PRACTICE PROBLEMS PRE-LAB-osM to osmosis and Tonicity, Practice Problems: this pre-lab exercise, each dialysis bag represents Like the plasma membrane, the dialysis tubing is selectively a The are which means (such as but the is in the solvent Water can move into or out the dialysis bag or \"model cell\", \"cell solute cannot. Whether the water moves into, moves out of or moves into and out of the equally depends on the environment outside of the \"cell\'; in this model system the environment is the solution in the beaker surrounding the dialysis bag. ully read introduction before completing the pre-lab assignment. Your textbook is also the a good reference for this assignment. Part Selectively permeable dialysis bags are used to represent three different cells placed in three different beakers. The cells contain NaCI in different concentrations of aqueous solutions. The cells are placed in beakers, which also contain different aqueous solutions of Naci. For each of the beakers, answer the questions below. Beaker #1 Beaker 2 Beaker 3 Cell 1 Cell 2 Cell 3 Cell 1 contains 50% NaCI Cell N 1 contains 30% NaCl Cell 1 contains 15% NaCl Beaker contains 25% NaCl Beaker contains 30% NaCl Beaker contains 35% NaCl a) The solution inside the cell contains 50% NaCl and water. b) The beaker contains 25% NaCl and water. c) The solution inside cell #1 is tonic to the solution outside cell #1. HI is tonic to the solution inside cell
A) The solution inside the cell contains 50% NaCl and _50%water.
B) The beaker contains 25% NaCl and __75_____ % water.
C) The solution \"inside\" cell #1 is hypertonic to the solution outside cell #1. concentration of NaCl is more than inside the cell .concentration of solute is les
D) The solution \"outside\" cell #1 is hypotonic to the solution inside cell #1. concentration of solute is less.