Fill in the values in the table below to give a legitimate p
| Fill in the  
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Solution
The sum of all the probabilities of a probability distribution of random variable should be equal to 1. So
P(X=-1)+P(X=2)+P(X=4)+P(X=5)+P(X=6)=1
P(X=-1)+P(X=2)+0.24+0.27+0.28=1
P(X=-1)+P(X=2)=1-0.79=0.21
So P(X=-1)+P(X=2) must be equal to 0.21 for legitimate probability distribution.

