FIGURE NOT DRAWN TO SCALE FA 84 kN FB 53 kN and a 245 deg

FIGURE NOT DRAWN TO SCALE! F_A = 8.4 kN. F_B = 5.3 kN and a = 24.5 deg. determine the angle theta for connecting member A in Deg so that the resultant force is directed horizontally to the right. Not yet answered Marked out of 5.0 Flag question 2- determine the magnitude of the resultant force in kN.

Solution

Part -1

If there is no vertical component of the force then :

F_A Cos () = F_B Cos(a)

Or, 8.4* Cos() = 5.3 * Cos(24.5°)

Or, Cos() = 0.5741

Or, = 54.96°

Part -2

Magnitude of the resultant force = F_A Sin() + F_B Sin(a) = 8.4*Sin(54.96°) + 5.3*Sin(24.5°)

                                                                                            = 9.075 kN