A survey of 25 randomly selected customers found the ages sh

A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.96 years and the standard deviation is 9.81 years.

Note that the standard error is given by

SE = s/sqrt(n)

Thus, if n = 25,

SE = 9.81/sqrt(25) = 1.962

If n = 225,

SE = 9.81/sqrt(225) = 0.654

We see that it decreased. Dividng them, 1.962/0.654 = 3.

Thus, it is

OPTION B: DECREASED, standard error is divided by 3. [ANSWER]