Solve the following using 8 digit nines complement arithmeti

Solve the following using 8 digit, nine\'s complement arithmetic: (71033.2 -83064.9)_10:

Solution

Ans)

e) 198₁₀=1100 0110₂, -198----1\'s compliment -198= 0011 1001

  77₁₀=0100 1101₂, -177----1\'s compliment -177=1011 0010

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-198-77=1110 1011

+1

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  -198-77=1110 1100

Magnitude by doing 1\'s compliment =0001 0011=19

So we get -198-77=-19 because with 8 bits we cannot represent -198-77=-275,so we get wrong answer,as you asked to do for 8-bit ,i have done the process ,ultimately you get wrong answer

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If we take 10 bits then result will be as follows

198₁₀=001100 0110₂, -198----1\'s compliment -198= 110011 1001

  77₁₀=000100 1101₂, -177----1\'s compliment -177= 111011 0010

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-198-77= 101110 1011

+1

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-198-77=101110 1100

Magnitude by doing 1\'s compliment =010001 0011=275

So we got the right answer this time -275

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