You discover a new population of ashy geckos on the Dry Tort

You discover a new population of ashy geckos on the Dry Tortugas that have emigrated from southern Florida. You collect the following genetic data for the enzyme cytochrome oxidase (cox), shown in the table below. Use these data to answer the following questions.

8a. What are the allelic frequencies for the Dry Tortugas population? 8b. What are the population’s genotypic frequencies? 8c. Is this population in H-W equilibrium? 8d. Offer an explanation (1-2 sentences) for your answer to 8c.

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gecko #

Sex

cox genotype

1

M

c₁c₂

2

M

c₁c₁

3

F

c₁c₁

4

M

c₂c₂

5

F

c₂c₂

6

F

c₁c₁

7

M

c₂c₂

8

M

c₂c₂

9

F

c₁c₂

10

M

c₁c₁

gecko #	Sex	cox genotype
1	M	c1c2
2	M	c1c1
3	F	c1c1
4	M	c2c2
5	F	c2c2
6	F	c1c1
7	M	c2c2
8	M	c2c2
9	F	c1c2
10	M	c1c1

Solution

8a.

If P represents frequency of allele C1 and quality represents frequency of allele C2. As per data given number of individuals

C1C1 = 4.

C2C2 = 4.

C1C2 = 2.

Allele frequency for Allele C1 =

P= f ( C1) = (2 x No. Of C1C1 ) + ( No. Of C1C2) / 2 × Total number of individuals in population.

= (2 × 4) + 2 ÷ 2 × 10 = 8 + 2 ÷ 20 = 10 ÷ 20 = 0.2.

Therefore frequency of Allele C1 = 0.2.

Frequency of Allele C2 = ( 2 ×No. Of C2C2) + (NO.of C1C2)/ 2 × Total number of individuals =

(2 ×4) + (2) ÷ 2 × 10 = 8 + 2 ÷ 20 = 10 ÷ 20 = 0.2

Allele frequency of C2 = 0.2.

8.B.

Genotypic frequency =

C1C1 = (0.2)2 = 0.04.

C2C2 = (0.2)2 = 0.04

C1C2 = 2×0.2×0.2 = 0.08.

8.C.

No this population is not in HW equilibrium.

8.D. The combination of allelic frequency of two alleles C1 and C2 does not match the equilibrium Value of 1.