For a normal distribution with a mean of 400 and a standard

For a normal distribution with a mean of 400 and a standard deviation of 25, the value 360 has a z value of

Solution

Normal Distribution
Mean ( u ) =400
Standard Deviation ( sd )=25
Normal Distribution = Z= X- u / sd ~ N(0,1)                  
P(X < 360) = (360-400)/25
= -40/25= -1.6

We got the Z value as -1.60