Homework Soursefind the absolute min and max of fx5lnx2 1 3x on 04 Give bot
find the absolute min and max of f(x)=5ln(x^2 +1) -3x on [0,4]. Give both x and y coordinates
Solution
f(x)=5ln(x^2 +1) -3x f\'(x) = 10x/(x^2+1) - 3 for critical point f\'(x) = 0 10x/(x^2+1) - 3 = 0 10x/(x^2+1) = 3 10x = 3x^2 + 3 3x^2 - 10x + 3 = 0 x = 3, 1/3 f(3) = 5ln10 - 3.....which is the absolute maximum value at x = 3 f(1/3) = 5ln(10/9) - 3.....which is the absolute minimum value at x = 1/3![find the absolute min and max of f(x)=5ln(x^2 +1) -3x on [0,4]. Give both x and y coordinatesSolution f(x)=5ln(x^2 +1) -3x f\'(x) = 10x/(x^2+1) - 3 for critical](/WebImages/28/find-the-absolute-min-and-max-of-fx5lnx2-1-3x-on-04-give-bot-1074762-1761563518-0.webp "find the absolute min and max of f(x)=5ln(x^2 +1) -3x on [0,4]. Give both x and y coordinatesSolution f(x)=5ln(x^2 +1) -3x f\'(x) = 10x/(x^2+1) - 3 for critical")
