Please Help A common measure of transmission for digital dat

Please Help

A common measure of transmission for digital data is the baud rate, defined as the number of bits transmitted per second. Generally, transmission is accomplished in packets consisting of a start bit, a byte (8 bits) of information, and a stop bit. Using these facts, answer the following: How many minutes would it take to transmit a 1024 Times 1024 image with 256 intensity levels using a 56k baud modem? High-definition television (HDTV) generates images with 1125 horizontal TV lines interlaced (where every other line is painted on the tube face in each of two fields, each field being 1/60^th of a second in duration). The width-to-height aspect ratio of the images is 16:9. The fact that the number of horizontal lines is fixed determines the vertical resolution of the images. A company has designed an image capture system that generates digital images from HDTV images. The resolution of each TV line in their system is in proportion to vertical resolution, with the proportion being the width-to-height ratio of the images. Each pixel in the color image has 24 bits of intensity resolution, 8 bits each for a red, a green, and a blue image. These three \"primary\" images from a color image. How many bits would it take to store a 2-hour HDTV movie?

Solution

1.

A baud is a unit of transmission speed of equal to the number of times a signal changes state per second.

The total amount of data transmit in given 8 bit

Given image is 1024 x 1024 = 2^20

                                                          or

                                                     1024^2

Used intensity levels 56k

Then the image 1024 x 1024 x [8+2] bits

Required time for transmit the given image at given 56k baud link

= 1024 x 1024 x[8+2] = 1024 x 1024 x10 = 10485760

10485760/56000 = 187.245 seconds

Convert it into seconds 187.245/60= 3.12 min

2.

Hdtv generates images with 1125 with horizontal interlaced lines

Width and height are 16:9

       16 : 9

        1125

L = Number of pixles of per line is

16/9 = L/1125

L =1125 x 16 / 9 = 2000

The image size is = 1125 x 2000 (frame size)

8bit image – 1/30 sec

For each red green blue component required seconds are 2 x 60 x 60 = 7200

In the given per second 30 frames so 2 hours per second 30 frames

The overall data rate or frames = (2000 x 1125) x 8 x 3 x30 = 2000 x 1125 x 720

                                                           = 1620000000. bits

	16 : 9