a the dipole is parallel to the electric field b the dipole
(a) the dipole is parallel to the electric field,
(b) the dipole is perpendicular to the electric field, and
(d) Find the potential energy of the dipole in the electric field for each case.
Solution
The torque on an electric dipole is given by
tau = pxE
potential energy of dipole is given by
U = -p.E
A. tau at theta = 0 deg
tau = pE*sin A = pE*sin 0 = 0
B. at theta = 90 deg
tau = 0.5*1.6*10^-19*10^-9*3*10^4*sin 90 = 2.4*10^-24 N-m
C. at theta = 30 deg
tau = 0.5*1.6*10^-19*10^-9*3*10^4*sin 30 = 1.2*10^-24 N-m
D. U = -pE*cos A
i. U = -pE*cos 0 = -0.5*1.6*10^-19*10^-9*3*10^4*cos 0 = -2.4*10^-24 J
ii. U = -0.5*1.6*10^-19*10^-9*3*10^4*cos 90 = 0 J
iii. U = -0.5*1.6*10^-19*10^-9*3*10^4*(cos 30 deg) = -2.078*10^-24 J
