Simplify the alternating sum using the Binomial TheoremSolut

Simplify the alternating sum using the Binomial Theorem

Solution

Note that

(a + b)^n = Sum [C(n, r) a^r b^(n - r)]

If we set

a = -3, b = 1,

(-3 + 1)^n = Sum [C(n, r) (-3)^r 1^(n - r)]

(-2)^n = Sum [C(n, r) (-3)^r]

Thus,

Sum[(-3)^r C(n, r)] = (-2)n [ANSWER]

Simplify the alternating sum using the Binomial TheoremSolutionNote that (a + b)^n = Sum [C(n, r) a^r b^(n - r)] If we set a = -3, b = 1, (-3 + 1)^n = Sum [C(n,

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